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How tall is Drew Hankinson in feet and inches?

6 feet and 7.1338582677166 inches
6 feet and 10 inches
100 feet and 10 inches
What is the height (length measured vertically) of Andrew William "Drew" Hankinson (born December 22, 1983), the American professional wrestler currently signed with World Wrestling Entertainment (WWE) appearing on its Raw brand under the ring name Festus in feet and inches, the compound of the two units (feet and inches)?
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Dave Batista's height is 6 ft 2.75 in (190 cm) US Wrestler. One of his claims was "I'm 6ft 5", someone mentioned they saw "6ft 3".

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